Statement-1 : Ions `Na^(+)`, `Mg^(2+)`, `Al^(3+)` are isoelectronic.
Statement-2 : In each ion, the total number of electrons are 10.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False
D. Statement-1 is False, Statement-2 is True

Answer

To solve the question, we need to analyze the two statements given:

**Statement-1**: Ions `Na^(+)`, `Mg^(2+)`, `Al^(3+)` are isoelectronic.
**Statement-2**: In each ion, the total number of electrons are 10.

### Step-by-Step Solution:

1. **Understanding Isoelectronic Species**:
- Isoelectronic species are atoms or ions that have the same number of electrons.

2. **Finding the Electron Configuration of Each Ion**:
- **Sodium Ion (`Na^(+)`)**:
- Sodium (Na) has an atomic number of 11, which means it has 11 electrons in its neutral state.
- The electronic configuration of Na is: `1s² 2s² 2p⁶ 3s¹`.
- When it loses one electron to form `Na^(+)`, it becomes: `1s² 2s² 2p⁶ 3s⁰`.
- Total electrons in `Na^(+)`: 2 (from 1s) + 2 (from 2s) + 6 (from 2p) = 10 electrons.

3. **Calculating for Magnesium Ion (`Mg^(2+)`)**:
- Magnesium (Mg) has an atomic number of 12, meaning it has 12 electrons in its neutral state.
- The electronic configuration of Mg is: `1s² 2s² 2p⁶ 3s²`.
- When it loses two electrons to form `Mg^(2+)`, it becomes: `1s² 2s² 2p⁶ 3s⁰`.
- Total electrons in `Mg^(2+)`: 2 (from 1s) + 2 (from 2s) + 6 (from 2p) = 10 electrons.

4. **Calculating for Aluminum Ion (`Al^(3+)`)**:
- Aluminum (Al) has an atomic number of 13, which means it has 13 electrons in its neutral state.
- The electronic configuration of Al is: `1s² 2s² 2p⁶ 3s² 3p¹`.
- When it loses three electrons to form `Al^(3+)`, it becomes: `1s² 2s² 2p⁶ 3s⁰ 3p⁰`.
- Total electrons in `Al^(3+)`: 2 (from 1s) + 2 (from 2s) + 6 (from 2p) = 10 electrons.

5. **Conclusion**:
- Since all three ions (`Na^(+)`, `Mg^(2+)`, and `Al^(3+)`) have the same number of electrons (10), they are indeed isoelectronic.
- Therefore, **Statement-1 is true** and **Statement-2 is also true**. Statement-2 correctly explains Statement-1.

### Final Answer:
Both statements are true, and Statement-2 is the correct explanation for Statement-1.

---