Home
Class 12
CHEMISTRY
Electromagnetic radiations of wavelength...

Electromagnetic radiations of wavelength 100 nm are just sufficient to ionize sodium atom. How can we calculate the ionization energy of sodium atom in kJ per mole?

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the ionization energy of a sodium atom in kJ per mole given that electromagnetic radiation of wavelength 100 nm is sufficient to ionize it, we can follow these steps: ### Step 1: Convert Wavelength to Meters The wavelength (λ) is given as 100 nm. We need to convert this into meters for our calculations. \[ \text{Wavelength in meters} = 100 \, \text{nm} = 100 \times 10^{-9} \, \text{m} = 1 \times 10^{-7} \, \text{m} \] **Hint:** Remember that 1 nm = \(10^{-9}\) m. ### Step 2: Use the Photon Energy Formula The energy (E) of a photon can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] Where: - \(h\) = Planck's constant = \(6.626 \times 10^{-34} \, \text{J s}\) - \(c\) = speed of light = \(3 \times 10^{8} \, \text{m/s}\) - \(\lambda\) = wavelength in meters Substituting the values: \[ E = \frac{(6.626 \times 10^{-34} \, \text{J s}) \times (3 \times 10^{8} \, \text{m/s})}{1 \times 10^{-7} \, \text{m}} \] ### Step 3: Calculate the Energy Now, we perform the calculation: \[ E = \frac{(6.626 \times 10^{-34}) \times (3 \times 10^{8})}{1 \times 10^{-7}} = 1.9878 \times 10^{-18} \, \text{J} \] **Hint:** Ensure you multiply the constants correctly and pay attention to the powers of ten. ### Step 4: Convert Energy to kJ per Mole To find the ionization energy in kJ per mole, we need to multiply the energy per photon by Avogadro's number (\(N_A = 6.022 \times 10^{23} \, \text{mol}^{-1}\)): \[ \text{Ionization Energy per mole} = E \times N_A \] \[ \text{Ionization Energy per mole} = (1.9878 \times 10^{-18} \, \text{J}) \times (6.022 \times 10^{23} \, \text{mol}^{-1}) \] Calculating this gives: \[ \text{Ionization Energy per mole} = 1192.8 \, \text{J/mol} \] ### Step 5: Convert Joules to Kilojoules Finally, we convert the energy from joules to kilojoules: \[ \text{Ionization Energy in kJ/mol} = \frac{1192.8 \, \text{J}}{1000} = 1.1928 \, \text{kJ/mol} \] **Hint:** Remember that to convert from joules to kilojoules, you divide by 1000. ### Final Answer The ionization energy of the sodium atom is approximately **1.1928 kJ/mol**.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - G (Interger Answer Type Questions)|8 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - H (Multiple True-False Type Questions) Identify the correct combination of true(T) and false(F) of the given three statements.|5 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - E (Assertion-Reason Type Questions)|10 Videos
  • BIOMOLECULES

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE (ASSIGNMENT) SECTION - D Assertion - Reason Type Questions|5 Videos
  • CHEMICAL KINETICS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION D : Assertion - Reason Type Questions)|15 Videos

Similar Questions

Explore conceptually related problems

Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom . Calculate the ionisation energy of sodium in kJ mol^(-1) .

Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom . Calculate the ionisation energy of sodium in kJ mol^(-1) .

Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise a sodium atom. Calculate the energy corresponding to this wavelength and the ionisation potential of Na.

Electromegnetic radiation of wavelength 500 nm is just safficient to ionic a sodium atom .Calculate the energy corresponding to this wavelength the ionisation potential of Na

The maximum wavelength of radiation that can ionize a sodium atom is 2414 A the ionization energy of sodium per mole shall be

The ionization energy of H-atom is 13.6eV . Calculate the is ionization energy of Li^(+2) ion-

When electromagnetic radiaiton of wavelength 300 nm falls on the surface of sodium electrons are emitted with a kinetic enegry of 1.68xx10^(5)Jmol^(-) . What is the minimum enegry needed to remove an electorn from sodium? Strategy: The minimum enegry required to remove an electron from target metal is called work function W_(0) of the metal. It can be calculated from Eq., provided we know the energy of the incident photon and kinetic enegry of a single photoelectorn.

The ionization of the ionized sodium atom N a^(10) is:

Consider a hydrogen atom with its electron in the n^(th) orbital An electomagnetic radiation of wavelength 90 nm is used to ionize the atom . If the kinetic energy of the ejected electron is 10.4 eV , then the value of n is ( hc = 1242 eVnm)

Calculate the weight of : 10.0 g atoms of sodium.