Statement-1 : All hybrid orbitals of same composition have same shape and energy .
Statement-2 : All hybrid orbitals on carbon in `CH_(3)Cl` have same s character .
Statement-3 : Hybridisation is a physical process .

Options

A. TFT
B. TTT
C. FFT
D. TFF

Answer

To analyze the given statements, we will evaluate each one step by step:

### Step 1: Evaluate Statement 1
**Statement 1**: All hybrid orbitals of the same composition have the same shape and energy.

**Solution**:
Hybrid orbitals are formed by the mixing of atomic orbitals. When atomic orbitals of the same type (for example, s and p orbitals) mix, they create hybrid orbitals that have the same shape and energy. This is because the hybridization process involves the combination of orbitals with similar characteristics. Therefore, this statement is **True**.

### Step 2: Evaluate Statement 2
**Statement 2**: All hybrid orbitals on carbon in CH₃Cl have the same s character.

**Solution**:
In CH₃Cl, the carbon atom undergoes sp³ hybridization. This means that one s orbital and three p orbitals mix to form four equivalent sp³ hybrid orbitals. Since all these hybrid orbitals are formed from the same atomic orbitals, they will have the same s character. In this case, the s character is 25% (1 s orbital out of 4 total orbitals). Therefore, this statement is also **True**.

### Step 3: Evaluate Statement 3
**Statement 3**: Hybridization is a physical process.

**Solution**:
Hybridization is a theoretical concept used to describe the formation of chemical bonds. It involves the mixing of atomic orbitals to form new hybrid orbitals that can participate in bonding. While it is a mathematical model, it is often considered a physical process because it occurs in the context of forming chemical bonds. Therefore, this statement is **True**.

### Conclusion
Since all three statements have been evaluated and found to be true, the correct option is that **all statements are true**.

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