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Statement-1 : NH(3) is pyramidal in shap...

Statement-1 : `NH_(3)` is pyramidal in shape .
Statement-2 : `SiCl_(4)` and `GaCl_(4)^(-)` are isostructural .
Statement-3 : `sd^(3)` hybridisation may be possible

A

TTF

B

TTT

C

FTT

D

TFT

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will evaluate each statement one by one. ### Step 1: Evaluate Statement 1 **Statement 1:** `NH3` is pyramidal in shape. - **Explanation:** In ammonia (NH3), nitrogen (N) is the central atom and has five valence electrons. It forms three bonds with hydrogen (H) atoms and has one lone pair of electrons. The presence of the lone pair affects the geometry of the molecule. The ideal geometry for four electron pairs (three bonding pairs and one lone pair) is tetrahedral. However, because of the lone pair, the shape of NH3 is trigonal pyramidal, with bond angles of approximately 107 degrees. - **Conclusion:** Statement 1 is **True**. ### Step 2: Evaluate Statement 2 **Statement 2:** `SiCl4` and `GaCl4^(-)` are isostructural. - **Explanation:** Silicon tetrachloride (SiCl4) has a silicon (Si) atom at the center with four chlorine (Cl) atoms bonded to it, resulting in a tetrahedral shape due to sp3 hybridization. Gallium tetrachloride anion (GaCl4^(-)) has gallium (Ga) at the center, which also forms four bonds with chlorine atoms. Although gallium has three valence electrons, the negative charge allows it to effectively use four orbitals for bonding, resulting in sp3 hybridization as well. Thus, both SiCl4 and GaCl4^(-) exhibit tetrahedral geometry. - **Conclusion:** Statement 2 is **True**. ### Step 3: Evaluate Statement 3 **Statement 3:** `sd^(3)` hybridization may be possible. - **Explanation:** Hybridization refers to the mixing of atomic orbitals to form new hybrid orbitals for bonding. The common types of hybridization include sp, sp2, sp3, dsp3, and d2sp3. However, `sd^3` hybridization is not recognized in standard hybridization theory. The filling of orbitals follows the Aufbau principle, and typically, d orbitals are involved in hybridizations with s and p orbitals, but not in the form of `sd^3`. Therefore, this statement is incorrect. - **Conclusion:** Statement 3 is **False**. ### Final Conclusion - Statement 1: True - Statement 2: True - Statement 3: False The correct answer is that Statements 1 and 2 are true, while Statement 3 is false. ---
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