A solution contains `Na_(2)CO_(3)` and `NaHCO_(3). 10 mL` of the solution required `2.5 mL "of" 0.1M H_(2)SO_(4)` for neutralisation using phenolphthalein as indicator. Methyl orange is then added when a further `2.5 mL "of" 0.2M H_(2)SO_(4)`was required. The amount of `Na_(2)CO_(3)` and `NaHCO_(3)` in `1 "litre"` of the solution is:

Options

A. `5.3 g and 4.2 g`
B. `3.3 g and 6.2 g`
C. `4.2 g and 5.3 g`
D. `6.2 g and 3.3 g`

Explanation

To solve the problem, we need to determine the amounts of sodium carbonate (Na₂CO₃) and sodium bicarbonate (NaHCO₃) in a solution based on the neutralization reactions with sulfuric acid (H₂SO₄).

### Step-by-Step Solution:

1. **Identify the Neutralization Reactions**:
- Sodium carbonate reacts with sulfuric acid to form sodium bicarbonate and sodium sulfate:
\[
\text{Na}_2\text{CO}_3 + \text{H}_2\text{SO}_4 \rightarrow \text{NaHCO}_3 + \text{Na}_2\text{SO}_4
...