`(A)+SbF_(5)to[XeF_(3)]^(+)[SbF_(6)]^(-)`
Compound (A) is

Options

A. `XeF_(2)`
B. `XeF_(4)`
C. `XeF_(6)`
D. Both 1 and 2

Answer

To solve the question, we need to identify the compound (A) that reacts with SbF5 to produce [XeF3]^(+) and [SbF6]^(-).

### Step-by-Step Solution:

1. **Understanding the Reaction**:
The reaction involves a compound (A) that reacts with antimony pentafluoride (SbF5). The products of the reaction are [XeF3]^(+) and [SbF6]^(-). This indicates a fluorine exchange reaction.

2. **Identifying the Reactants**:
We know that SbF5 is a strong fluorinating agent. It can react with xenon fluorides. The presence of [XeF3]^(+) suggests that xenon is involved in the reaction.

3. **Considering Xenon Fluorides**:
The common xenon fluorides are XeF2, XeF4, and XeF6. We need to determine which of these could be compound (A) that can react with SbF5 to produce the given products.

4. **Analyzing Possible Compounds**:
- **XeF2**: This compound does not have enough fluorine to produce [XeF3]^(+).
- **XeF4**: This compound has the potential to lose a fluorine atom when reacting with SbF5, leading to the formation of [XeF3]^(+) and [SbF6]^(-).
- **XeF6**: This compound has too many fluorine atoms and would not lead to the formation of [XeF3]^(+).

5. **Conclusion**:
The only suitable candidate for compound (A) that can react with SbF5 to yield the products [XeF3]^(+) and [SbF6]^(-) is **XeF4**.

Thus, the answer is:
**Compound (A) is XeF4.**