`Cl_(2)` on reaction with excess of `NH_(3)` gives

Options

A. `NH_(4)Cl+N_(2)`
B. `NCl_(3)+HCl`
C. `NCl_(3)Cl` only
D. `NH_(4)Cl+NCl_(3)`

Answer

To solve the question "Cl₂ on reaction with excess of NH₃ gives," we need to analyze the reaction between chlorine gas (Cl₂) and ammonia (NH₃).

### Step-by-Step Solution:

1. **Understand the Reactants**: We have chlorine gas (Cl₂) and ammonia (NH₃) as reactants.

2. **Identify the Reaction Conditions**: The problem states that Cl₂ is reacted with excess NH₃. This indicates that there is more NH₃ available than is needed to react with Cl₂.

3. **Write the Reaction**: When Cl₂ reacts with NH₃, several products can be formed depending on the conditions. The primary reaction can be represented as:
\[ 3 \text{Cl}_2 + 8 \text{NH}_3 \rightarrow 6 \text{NH}_4\text{Cl} + \text{N}_2 \]
This indicates that chlorine reacts with ammonia to form ammonium chloride (NH₄Cl) and nitrogen gas (N₂).

4. **Consider Excess NH₃**: Since we have excess NH₃, it can lead to the formation of additional products. In the presence of excess chlorine, the reaction can also yield:
\[ \text{NH}_3 + \text{Cl}_2 \rightarrow \text{NHCl}_3 + \text{HCl} \]
Here, nitrogen trichloride (NHCl₃) and hydrochloric acid (HCl) are formed.

5. **Evaluate the Options**: Now, we can evaluate the options given in the question:
- **Option 1**: NH₄Cl + N₂
- **Option 2**: NHCl₃ + HCl
- **Option 3**: NHCl₃Cl
- **Option 4**: NH₄Cl + NHCl₃

Based on our reaction analysis, the products formed include NH₄Cl and N₂, which corresponds to Option 1.

6. **Conclusion**: The correct answer to the question is:
\[ \text{Cl}_2 \text{ on reaction with excess of } \text{NH}_3 \text{ gives } \text{NH}_4\text{Cl} + \text{N}_2. \]

### Final Answer:
**The answer is Option 1: NH₄Cl + N₂.**