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Nitrogen forms largest number of oxides ...

Nitrogen forms largest number of oxides in which oxidation state of nitrogen varies from +1 to +5 `N_(2)O,NO,N_(2)O_(3),N_(2)O_(4) and N_(2)O_(5)` respectively. The largest number of oxides are formed due to capability of forming stable multiple bonds by nitrogen with oxygen.
Q. Which of the following statements is/are correct regarding oxides of nitrogen?

A

Dinitrogen trioxide dissolves in KOH forming potassium nitrate

B

Aqueous solution by nitrogen dioxide behave both as a reducing an as an oxidising agent

C

Nitrous oxide is fairly soluble in cold water and turns blue litmus red

D

Nitrogen dioxide is soluble in water to form nitric acid only

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statements regarding the oxides of nitrogen are correct, we will analyze each statement one by one based on the information provided about nitrogen oxides. ### Step-by-Step Solution: 1. **Statement 1: Dinitrogen trioxide dissolves in KOH forming potassium nitrate.** - Dinitrogen trioxide (N₂O₃) reacts with potassium hydroxide (KOH) to form potassium nitrite (KNO₂) and water. The reaction is: \[ N_2O_3 + 2 KOH \rightarrow 2 KNO_2 + H_2O \] - Since the statement claims it forms potassium nitrate (KNO₃), this statement is **incorrect**. 2. **Statement 2: Aqueous solution of nitrogen dioxide behaves both as a reducing and as an oxidizing agent.** - Nitrogen dioxide (NO₂) in an aqueous solution can form nitrous acid (HNO₂) and nitric acid (HNO₃): \[ 2 NO_2 + H_2O \rightarrow HNO_2 + HNO_3 \] - In this reaction, nitrogen goes from +4 in NO₂ to +3 in HNO₂ (reduction) and +5 in HNO₃ (oxidation). Therefore, NO₂ can act as both a reducing agent and an oxidizing agent. This statement is **correct**. 3. **Statement 3: Nitrous oxide is fairly soluble in cold water and turns blue litmus to red.** - Nitrous oxide (N₂O) is a neutral oxide and does not exhibit acidic properties. Therefore, it will not turn blue litmus paper red. This statement is **incorrect**. 4. **Statement 4: Nitrogen dioxide is soluble in water to form nitric acid only.** - As previously mentioned, nitrogen dioxide reacts with water to form both nitrous acid (HNO₂) and nitric acid (HNO₃). Thus, the statement that it forms nitric acid only is **incorrect**. ### Conclusion: The only correct statement regarding the oxides of nitrogen is **Statement 2**. ### Summary of Correctness: - Statement 1: Incorrect - Statement 2: Correct - Statement 3: Incorrect - Statement 4: Incorrect
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