Number of oxygen atoms shared per `SiO_(4)^(4-)` tetrahedron in single chain silicates are `"_________________"`.

Answer

To solve the question regarding the number of oxygen atoms shared per \( \text{SiO}_4^{4-} \) tetrahedron in single chain silicates, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Structure of \( \text{SiO}_4^{4-} \)**:
- The \( \text{SiO}_4^{4-} \) tetrahedron consists of one silicon atom (Si) at the center and four oxygen atoms (O) at the corners of the tetrahedron. Each oxygen atom carries a negative charge.

2. **Identify the Nature of Single Chain Silicates**:
- In single chain silicates, the tetrahedral units (i.e., \( \text{SiO}_4^{4-} \)) are linked together in a chain-like structure. This occurs through the sharing of oxygen atoms between adjacent tetrahedra.

3. **Determine the Sharing of Oxygen Atoms**:
- In a single chain silicate, each tetrahedron shares two of its oxygen atoms with neighboring tetrahedra. This means that for every \( \text{SiO}_4^{4-} \) unit, two oxygen atoms are involved in bonding with adjacent tetrahedra.

4. **Conclusion**:
- Therefore, the number of oxygen atoms shared per \( \text{SiO}_4^{4-} \) tetrahedron in single chain silicates is **2**.

### Final Answer:
The number of oxygen atoms shared per \( \text{SiO}_4^{4-} \) tetrahedron in single chain silicates is **2**.

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