What is the Oxidation number of Xe in mixture of `XeF_(6) and XeF_(4) `?

Answer

To find the oxidation number of xenon (Xe) in the mixture of XeF6 and XeF4, we will analyze each compound separately.

### Step 1: Determine the oxidation number of Xe in XeF6

1. **Identify the compound**: The first compound is xenon hexafluoride (XeF6).
2. **Assign oxidation states**: The oxidation state of fluorine (F) is -1.
3. **Set up the equation**: Let the oxidation state of xenon be \( x \). Since there are 6 fluorine atoms, the equation becomes:
\[ x + 6(-1) = 0 \]
4. **Solve the equation**:
\[ x - 6 = 0 \\ x = +6 \]
5. **Conclusion**: The oxidation number of xenon in XeF6 is +6.

### Step 2: Determine the oxidation number of Xe in XeF4

1. **Identify the compound**: The second compound is xenon tetrafluoride (XeF4).
2. **Assign oxidation states**: Again, the oxidation state of fluorine (F) is -1.
3. **Set up the equation**: Let the oxidation state of xenon be \( x \). Since there are 4 fluorine atoms, the equation becomes:
\[ x + 4(-1) = 0 \]
4. **Solve the equation**:
\[ x - 4 = 0 \\ x = +4 \]
5. **Conclusion**: The oxidation number of xenon in XeF4 is +4.

### Final Answer

In the mixture of XeF6 and XeF4, the oxidation number of xenon is +6 in XeF6 and +4 in XeF4.

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