How many N-O bonds are present in product when `NH_(4)NO_(3)` is strongly heated (above `300^(@)C`)?

Answer

To solve the question of how many N-O bonds are present in the product when ammonium nitrate (NH₄NO₃) is strongly heated above 300°C, we can follow these steps:

### Step 1: Identify the decomposition reaction of NH₄NO₃
When ammonium nitrate is heated above 300°C, it decomposes into nitrogen oxide (N₂O) and water (H₂O). The reaction can be represented as:
\[ \text{NH}_4\text{NO}_3 \rightarrow \text{N}_2\text{O} + \text{H}_2\text{O} \]

### Step 2: Determine the major product
The major product of this reaction is nitrous oxide (N₂O).

### Step 3: Analyze the structure of N₂O
To find out how many N-O bonds are in N₂O, we need to look at its molecular structure. The structure of N₂O can be represented as:
- Nitrogen (N) is bonded to another nitrogen (N) with a triple bond.
- The second nitrogen (N) is bonded to oxygen (O) with a single bond.

The structural representation can be simplified as:
\[ \text{N} \equiv \text{N} - \text{O} \]

### Step 4: Count the N-O bonds
In the structure of N₂O, there is one N-O bond present.

### Conclusion
Thus, when ammonium nitrate (NH₄NO₃) is strongly heated above 300°C, the product N₂O contains **one N-O bond**.

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