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NH(3)+NaOCl to NH(2)-NH(2)+NH(4)Cl To ...

`NH_(3)+NaOCl ``to`` NH_(2)-NH_(2)+NH_(4)Cl`
To obtain this product in large amount, we should use

A

Tap water as medium

B

Glue or gelatine in medium

C

Heavy metal ion in solution

D

by takin NaOCl in excess amount

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the reaction of ammonia (NH₃) with sodium hypochlorite (NaOCl) to produce hydrazine (NH₂-NH₂) and ammonium chloride (NH₄Cl), we need to follow these steps: ### Step 1: Understand the Reaction The reaction involves ammonia reacting with sodium hypochlorite to produce hydrazine and ammonium chloride. The overall reaction can be simplified as: \[ 2 \text{NH}_3 + \text{NaOCl} \rightarrow \text{N}_2\text{H}_4 + \text{NaCl} + \text{H}_2\text{O} \] ### Step 2: Identify Conditions for Maximum Yield To obtain hydrazine in large amounts, we need to ensure that the reaction conditions favor the formation of hydrazine rather than its further oxidation to nitrogen gas (N₂). ### Step 3: Use of Catalysts The presence of certain substances can help in controlling the reaction. Specifically, using glue or gelatin can catalyze the reaction and slow down the oxidation of hydrazine to nitrogen gas. This is crucial because if hydrazine is oxidized, it will not accumulate in large amounts. ### Step 4: Conclusion Therefore, to obtain hydrazine in large amounts from the reaction of ammonia and sodium hypochlorite, we should use glue or gelatin as a catalyst. This prevents the oxidation of hydrazine and allows for a higher yield of the desired product. ### Final Answer To obtain the product in large amounts, we should use **glue or gelatin**. ---
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