Addition of `K_(4)[Fe(CN)_(6)]` solution to `FeCl_(3)` solution gives

Options

A. Ferro-ferrocyanide
B. Ferro-ferricyanide
C. Ferri-ferrocyanide
D. Ferri-ferricyanide

Answer

To solve the question regarding the addition of \( K_4[Fe(CN)_6] \) solution to \( FeCl_3 \) solution, we can follow these steps:

### Step 1: Identify the Reactants
We have two reactants:
- \( K_4[Fe(CN)_6] \) (Potassium hexacyanoferrate(II))
- \( FeCl_3 \) (Ferric chloride)

### Step 2: Determine the Oxidation States
- In \( K_4[Fe(CN)_6] \), the oxidation state of iron (Fe) is +2.
- In \( FeCl_3 \), the oxidation state of iron (Fe) is +3.

### Step 3: Write the Reaction
When \( K_4[Fe(CN)_6] \) is added to \( FeCl_3 \), a reaction occurs where the iron in \( K_4[Fe(CN)_6] \) is oxidized from +2 to +3, and a complex is formed. The balanced equation for the reaction is:

\[ 3 K_4[Fe(CN)_6] + 4 FeCl_3 \rightarrow Fe_3[Fe(CN)_6]_2 + 12 KCl \]

### Step 4: Identify the Product
The product formed is \( Fe_3[Fe(CN)_6]_2 \), which is known as Prussian blue. This compound has a characteristic blue color.

### Step 5: Conclusion
The addition of \( K_4[Fe(CN)_6] \) to \( FeCl_3 \) results in the formation of Prussian blue, represented by the formula \( Fe_3[Fe(CN)_6]_2 \), along with potassium chloride \( KCl \).

### Final Answer
The addition of \( K_4[Fe(CN)_6] \) solution to \( FeCl_3 \) solution gives Prussian blue (\( Fe_3[Fe(CN)_6]_2 \)) and potassium chloride (\( KCl \)).

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