To determine which aqueous solution will have a pH less than 7, we need to analyze the compounds given in the question: TiCl4, FeCl3, and CuSO4.
### Step 1: Analyze TiCl4
- **Dissociation**: When TiCl4 is dissolved in water, it dissociates into Ti⁴⁺ and Cl⁻ ions.
- **Acid-Base Nature**: Ti⁴⁺ can hydrolyze to form Ti(OH)₄, which is a weak base. The Cl⁻ ion comes from HCl, a strong acid.
- **Conclusion**: Since it is formed from a weak base (Ti(OH)₄) and a strong acid (HCl), TiCl4 will be acidic in nature, resulting in a pH less than 7.
### Step 2: Analyze FeCl3
- **Dissociation**: FeCl3 dissociates into Fe³⁺ and Cl⁻ ions in water.
- **Acid-Base Nature**: Fe³⁺ can hydrolyze to form Fe(OH)₃, which is a weak base. The Cl⁻ ion again comes from HCl, a strong acid.
- **Conclusion**: Similar to TiCl4, FeCl3 is formed from a weak base (Fe(OH)₃) and a strong acid (HCl), making it acidic and resulting in a pH less than 7.
### Step 3: Analyze CuSO4
- **Dissociation**: CuSO4 dissociates into Cu²⁺ and SO₄²⁻ ions.
- **Acid-Base Nature**: Cu²⁺ can hydrolyze to form Cu(OH)₂, which is a weak base. The SO₄²⁻ ion comes from H₂SO₄, a strong acid.
- **Conclusion**: CuSO4, like the previous compounds, is formed from a weak base (Cu(OH)₂) and a strong acid (H₂SO₄), leading to an acidic solution with a pH less than 7.
### Step 4: Final Conclusion
- All three compounds (TiCl4, FeCl3, and CuSO4) lead to acidic solutions when dissolved in water, resulting in a pH less than 7.
- Therefore, the correct answer is **D) All of these**.