STATEMENT-1 : `MnO_(4)^(-)` is tetrahedral in shape .
and
STATEMENT-2: `KMnO_(4)` is purple in colour .

Options

A. Statement-1 is True , Statement-2 is True , Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True , Statement-2 is True , Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True , Statement-2 is False
D. Statement-1 is False , Statement-2 is True

Answer

To solve the problem, we need to analyze both statements regarding the compound \( \text{MnO}_4^- \) and \( \text{KMnO}_4 \).

### Step 1: Analyze Statement 1
**Statement 1:** \( \text{MnO}_4^- \) is tetrahedral in shape.

1. **Determine the oxidation state of manganese (Mn) in \( \text{MnO}_4^- \):**
- Let the oxidation state of Mn be \( x \).
- The oxidation state of oxygen is \(-2\).
- The equation becomes:
\[ x + 4(-2) = -1 \implies x - 8 = -1 \implies x = +7 \]
- Thus, the oxidation state of Mn in \( \text{MnO}_4^- \) is +7.

2. **Identify the hybridization:**
- In \( \text{MnO}_4^- \), Mn has no d-electrons in the +7 oxidation state, and the 4s and 3d orbitals can participate in bonding.
- The hybridization involves the 3d and 4s orbitals, resulting in \( \text{d}^3\text{s}^1 \) hybridization, which leads to a tetrahedral geometry.

3. **Conclusion for Statement 1:**
- Therefore, Statement 1 is **true**: \( \text{MnO}_4^- \) is tetrahedral in shape.

### Step 2: Analyze Statement 2
**Statement 2:** \( \text{KMnO}_4 \) is purple in color.

1. **Understand the color of \( \text{KMnO}_4 \):**
- The purple color of \( \text{KMnO}_4 \) is due to the presence of \( \text{MnO}_4^- \) ions.
- In \( \text{MnO}_4^- \), the color arises from a charge transfer transition rather than a d-d transition, as Mn is in the +7 oxidation state and has no d-electrons.

2. **Conclusion for Statement 2:**
- Therefore, Statement 2 is also **true**: \( \text{KMnO}_4 \) is purple in color.

### Step 3: Determine the relationship between the statements
- Both statements are true, but Statement 2 does not explain why Statement 1 is true. The color of \( \text{KMnO}_4 \) is due to charge transfer, not directly related to the tetrahedral shape of \( \text{MnO}_4^- \).

### Final Conclusion
- **Correct Option:** Statement 1 is true, Statement 2 is true, but Statement 2 is not a correct explanation for Statement 1.