Home
Class 12
CHEMISTRY
STATEMENT-1: The ground state conjfigura...

STATEMENT-1: The ground state conjfiguration of Cr is `3d^(5)4_((s)^(1))`
A set of half-filled orbitals containing one electrons each with their spin parallel provides extrs stability.

A

Statement-1 is True , Statement-2 is True , Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True , Statement-2 is True , Statement-2 is NOT a correct explanation for Statement-1

C

Statement-1 is True , Statement-2 is False

D

Statement-1 is False , Statement-2 is True

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • THE D AND F-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assingment ( Section-F Matrix-Match Type Questions )|3 Videos

  • THE D AND F-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assingment ( Section-G Integer Answer Type Questions )|5 Videos

  • THE D AND F-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assingment ( Section-D Linked Comprehension Type Questions ) Comprehension-II|3 Videos

  • Test-12

    AAKASH INSTITUTE ENGLISH|Exercise Exercise|58 Videos

  • THE P-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section-J)|16 Videos

Similar Questions

Explore conceptually related problems

Statement-I : The ground state configuration of Cr is 3d^(5) 4s^(1) . Because Statement-II : A set of exactly half filled orbitals containing parallel spin arrangement provide extra stability.

Statement-I : The ground state configuration of Cr is 3d^(5) 4s^(1) . Because Statement-II : A set of exactly half filled orbitals containing parallel spin arrangement provide extra stability.

The orbital configuration of ._(24)Cr is 3d^(5) 4s^(1) . The number of unpaired electrons in Cr^(3+) (g) is

Why does chromium have configuration of type 3d^(5) 4s^(1) instead of 3d^(4) 4s^(2) ?

STATEMENT-1: The ground state electronic configuration of nitrogen is STATEMENT-2: Electronic are filled in orbitals as per aufbau principle, Hund's rule of maximum spin multiplicity and pauli's principle.

Statement-1 : The groundstate configuration of Cr is [Ar] 3d^(5) 4s^(1) Statement-2 : The energy of atom is lesser in 3d^(5)4s^(1) configuration compared to 3d^(4)4s^(2) configuration.

The electronic configuration of an element is 3d^5 4s^1 . Write its (i) most stable oxidation state (ii) most oxidising state.

Assertion : The outer electronic configuration of Cr and Cu are 3d^(5) 4s^(1) and 3d^(10) 4s^(1) respectively . Reason : Electrons are filled in orbitals in order of increasing energies given by (n+l) rule.

The electronic configuration of valence shell of Cu is 3d^(10)4s^(1) and not 3d^(9)4s^(2) . How is this configuration explained?

Assertion-The free gaseous Cr atom has six unpaired electrons. Reason-Half-filled s-orbital has greater stability.