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A compound (A) when treated with Kl give...

A compound (A) when treated with Kl gives a Scarlet red ppt. (B) which dissolves in excess of Kl. This solution is made alkaline with NaOH and gave brown precipitate (C) when `NH_(3)` gas is passed through it. When (A) is added with small amount of `SnCl_(2)` it gives a white ppt (D) but gives grey precipitate with excess amount of `SnCl_(2)`. When `H_(2)S` gas is passed through an acidic solution of (A) a black precipitate (E) is obtained. Identify (A) to (E). Write the reactions involved.

Text Solution

AI Generated Solution

To solve the problem step by step, we will identify the compounds (A) to (E) and write the corresponding reactions involved. ### Step 1: Identify Compound A - **Given:** Compound (A) reacts with KI to give a scarlet red precipitate (B). - **Observation:** The scarlet red precipitate indicates the presence of mercuric iodide (HgI2). - **Conclusion:** Compound (A) is mercuric chloride (HgCl2). ### Step 2: Identify Compound B ...
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