If silver nitrate solution is added to a salt solution and a yellow precipitate is obtained the salt may contain

Options

A. `Br^(-)`
B. `l^(-)`
C. `Cl^(-)`
D. `F^(-)`

Answer

To solve the question regarding the yellow precipitate formed when silver nitrate solution is added to a salt solution, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Reaction**: When silver nitrate (AgNO3) is added to a salt solution, it can react with halide ions present in the salt. The halides of interest here are bromide (Br⁻), iodide (I⁻), and fluoride (F⁻).

2. **Identifying the Precipitate**: The yellow precipitate indicates the formation of a silver halide. The relevant reactions are:
- Silver bromide (AgBr) forms a yellow precipitate when reacting with bromide ions.
- Silver iodide (AgI) also forms a yellow precipitate when reacting with iodide ions.
- Silver fluoride (AgF) is colorless in its hydrated form but can appear yellow when dehydrated.

3. **Writing the Chemical Equations**:
- For bromide:
\[ \text{AgNO}_3 + \text{NaBr} \rightarrow \text{NaNO}_3 + \text{AgBr (yellow precipitate)} \]
- For iodide:
\[ \text{AgNO}_3 + \text{NaI} \rightarrow \text{NaNO}_3 + \text{AgI (yellow precipitate)} \]
- For fluoride (in dehydrated form):
\[ \text{AgNO}_3 + \text{NaF} \rightarrow \text{NaNO}_3 + \text{AgF (yellow in anhydrous form)} \]

4. **Conclusion**: Since the yellow precipitate can be formed from either bromide or iodide ions, the salt solution may contain either Br⁻ or I⁻ ions. Additionally, it can also contain F⁻ ions in certain conditions. Therefore, the salt may contain:
- Bromide ions (Br⁻)
- Iodide ions (I⁻)
- Fluoride ions (F⁻)

### Final Answer:
The salt may contain bromide (Br⁻), iodide (I⁻), or fluoride (F⁻) ions.

---