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Draw the Structure of BromoBenzene...

Draw the Structure of BromoBenzene

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To draw the structure of Bromobenzene, follow these steps: ### Step-by-Step Solution: 1. **Understand the Composition**: - Bromobenzene is an aryl halide, which means it contains a benzene ring with a bromine atom attached to it. The molecular formula is C6H5Br. 2. **Draw the Benzene Ring**: - Start by drawing a hexagon to represent the benzene ring. Benzene consists of six carbon atoms arranged in a ring, with alternating double bonds. However, for simplicity, you can just draw a hexagon and indicate the presence of double bonds with a circle inside or by alternating single and double lines. 3. **Add the Hydrogen Atoms**: - Each carbon in the benzene ring is bonded to one hydrogen atom. Since there are six carbon atoms, there will be six hydrogen atoms initially attached to the benzene ring. 4. **Substitute One Hydrogen with Bromine**: - To represent bromobenzene, you need to replace one of the hydrogen atoms on the benzene ring with a bromine (Br) atom. Choose any one of the carbon atoms and draw a bond to a bromine atom. 5. **Final Structure**: - The final structure will show a benzene ring with one bromine atom attached to it, indicating that one hydrogen has been replaced by bromine. ### Final Structure: ``` Br | C6H5 - C / \ C C | | C C \ / C - C ``` (Note: The above representation is a simplified version. In a more precise drawing, you would show the double bonds clearly.)
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