STATEMENT - 1 : `Co^(2+)` gives green colour with `Br_(2)` water in presence of `KHCO_(3)`
and
STATEMENT - 2 : Green colour is due to formation of `CoCO_(3)`.

Options

A. Statement-1 is True, Statement-2, is True, Statement-2 is a correct explanation for Statement-5
B. Statement-1 is True, Statement-2, is True, Statement-2 is NOT a correct explanation for Statement-5
C. Statement-1 is True, Statement-2 is False
D. Statement-1 is False, Statement-2 is True

Answer

To analyze the given statements regarding cobalt ions and their reactions, we can break down the solution into clear steps:

### Step 1: Analyze Statement 1
- **Statement 1** claims that `Co^(2+)` gives a green color with `Br2` water in the presence of `KHCO3`.
- When `Co^(2+)` (cobalt(II) ions) reacts with bromine water (`Br2`), in the presence of potassium hydrogen carbonate (`KHCO3`), it forms cobalt bromide, specifically cobalt(II) bromide hexahydrate (`CoBr2·6H2O`), which is purple in color.
- Upon heating, this hexahydrate can lose water to form an anhydrous form of cobalt(II) bromide, which is green in color.

### Step 2: Analyze Statement 2
- **Statement 2** claims that the green color is due to the formation of `CoCO3` (cobalt(II) carbonate).
- However, the green color observed is not due to `CoCO3` but rather due to the formation of the anhydrous cobalt(II) bromide (`CoBr2`), which is green. `CoCO3` does not play a role in this reaction.

### Conclusion
- **Statement 1** is correct because cobalt(II) ions do indeed produce a green color when reacting with bromine water in the presence of `KHCO3`.
- **Statement 2** is incorrect because the green color is due to the formation of `CoBr2`, not `CoCO3`.

### Final Answer
- Therefore, the correct option is that **Statement 1 is true and Statement 2 is false**.

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