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STATEMENT - 1 : Cu^(+2) is unstable in p...

STATEMENT - 1 : `Cu^(+2)` is unstable in presence of `Cl^(-)` ion.
and
STATEMENT - 2 : Formation of `CuCl` is more favourable.

A

Statement-1 is True, Statement-2, is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2, is True, Statement-2 is NOT a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will evaluate each statement step by step. ### Step 1: Evaluate Statement 1 **Statement 1:** `Cu^(+2)` is unstable in the presence of `Cl^(-)` ion. - **Analysis:** - `Cu^(+2)` is a cation with a +2 charge. - `Cl^(-)` is an anion with a -1 charge. - The presence of opposite charges leads to strong electrostatic attraction between the two ions. - According to Fajan's rule, a cation with a high positive charge and small size (like `Cu^(+2)`) has high polarizing power, which means it can distort the electron cloud of the anion (`Cl^(-)`). - This strong attraction indicates that `Cu^(+2)` is likely to form a bond with `Cl^(-)`, leading to the formation of `CuCl`. **Conclusion for Statement 1:** True. `Cu^(+2)` is unstable in the presence of `Cl^(-)` because it tends to form a stable compound (`CuCl`). ### Step 2: Evaluate Statement 2 **Statement 2:** Formation of `CuCl` is more favorable. - **Analysis:** - `CuCl` is formed when `Cu^(+1)` combines with `Cl^(-)`. - However, `Cu` has a higher tendency to exist in the +2 oxidation state (`Cu^(+2)`) rather than the +1 state because it is more stable in that state due to its polarizing power and hydration energy. - The formation of `CuCl` is less favorable compared to `CuCl2` because `Cu^(+2)` is more stable and forms stronger ionic bonds. - Therefore, the formation of `CuCl` is not the most favorable pathway; instead, `CuCl2` is more favorable. **Conclusion for Statement 2:** False. The formation of `CuCl` is not more favorable; `CuCl2` is more favorable. ### Final Conclusion - **Statement 1:** True - **Statement 2:** False ### Answer The correct option is **Option 3:** Statement 1 is true, Statement 2 is false. ---
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