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0.92 g of Ag(2)CO(3) is heated strongly ...

0.92 g of `Ag_(2)CO_(3)` is heated strongly beyond its melting point . After heating the amount of residue is

A

0.36 g

B

0.39 g

C

0.77 g

D

0.72 g

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The correct Answer is:
To solve the problem of determining the amount of residue left after heating 0.92 g of silver carbonate (Ag₂CO₃), we will follow these steps: ### Step 1: Write the decomposition reaction When silver carbonate (Ag₂CO₃) is heated, it decomposes into silver (Ag), carbon dioxide (CO₂), and oxygen (O₂). The balanced chemical equation for this reaction is: \[ 2 \text{Ag}_2\text{CO}_3 \rightarrow 4 \text{Ag} + 2 \text{CO}_2 + \text{O}_2 \] ### Step 2: Calculate the molar mass of silver carbonate (Ag₂CO₃) To find the molar mass of Ag₂CO₃, we need the atomic masses of its constituent elements: - Silver (Ag): 108 g/mol - Carbon (C): 12 g/mol - Oxygen (O): 16 g/mol The molar mass of Ag₂CO₃ is calculated as follows: \[ \text{Molar mass of Ag}_2\text{CO}_3 = 2 \times 108 + 12 + 3 \times 16 \] \[ = 216 + 12 + 48 = 276 \text{ g/mol} \] ### Step 3: Determine the number of moles of Ag₂CO₃ in 0.92 g Using the molar mass calculated, we can find the number of moles of Ag₂CO₃ in 0.92 g: \[ \text{Number of moles of Ag}_2\text{CO}_3 = \frac{\text{mass}}{\text{molar mass}} = \frac{0.92 \text{ g}}{276 \text{ g/mol}} \approx 0.00333 \text{ moles} \] ### Step 4: Calculate the amount of silver produced From the balanced equation, 2 moles of Ag₂CO₃ produce 4 moles of Ag. Therefore, the ratio of moles of Ag produced to moles of Ag₂CO₃ is: \[ \frac{4 \text{ moles Ag}}{2 \text{ moles Ag}_2\text{CO}_3} = 2 \] Thus, the number of moles of Ag produced from 0.00333 moles of Ag₂CO₃ is: \[ \text{Moles of Ag} = 0.00333 \times 2 = 0.00666 \text{ moles} \] ### Step 5: Calculate the mass of silver produced Now, we can calculate the mass of silver produced using its molar mass: \[ \text{Mass of Ag} = \text{moles} \times \text{molar mass} = 0.00666 \text{ moles} \times 108 \text{ g/mol} \approx 0.72 \text{ g} \] ### Conclusion The amount of residue left after heating 0.92 g of Ag₂CO₃ is approximately 0.72 g of silver.
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