The weight of 1 mole of a gas of density `0.2843gL^(-)`at NTP is

Answer

To find the weight of 1 mole of a gas with a given density at Normal Temperature and Pressure (NTP), we can use the relationship between mass, volume, and density.

### Step-by-Step Solution:

1. **Understand the relationship between mass, volume, and density**:
The mass of a substance can be calculated using the formula:
\[ \text{Mass} = \text{Density} \times \text{Volume} \]

2. **Identify the volume of 1 mole of gas at NTP**:
At NTP (Normal Temperature and Pressure), 1 mole of any ideal gas occupies a volume of:
\[ V = 22.4 \, \text{L} \]

3. **Use the given density**:
The density of the gas is given as:
\[ \text{Density} = 0.2843 \, \text{g/L} \]

4. **Calculate the mass of 1 mole of the gas**:
Using the formula from step 1, we can substitute the values for density and volume:
\[ \text{Mass} = \text{Density} \times \text{Volume} = 0.2843 \, \text{g/L} \times 22.4 \, \text{L} \]

5. **Perform the multiplication**:
\[ \text{Mass} = 0.2843 \times 22.4 = 6.36832 \, \text{g} \]

6. **Round the result**:
The mass of the gas can be rounded to an appropriate number of significant figures:
\[ \text{Mass} \approx 6.37 \, \text{g} \]

### Final Answer:
The weight of 1 mole of the gas is approximately **6.37 grams**.