What weight of solute (mol. Wt. 60) is required to dissolve in 180 g of water to reduce the vapour pressure to `4//5^(th)` of pure water ?

Explanation

To solve the problem of determining the weight of solute required to dissolve in 180 g of water to reduce the vapor pressure to \( \frac{4}{5} \) of pure water, we can follow these steps:

### Step 1: Understand the relationship between vapor pressures
According to Raoult's law, the relative lowering of vapor pressure (\( \Delta P \)) is given by:
\[ \Delta P = \frac{P_0 - P_s}{P_0} = \text{Mole Fraction of Solute} \]
Where:
...