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In 100 g naphthalene 2.56 g sulphur is a...

In 100 g naphthalene 2.56 g sulphur is added boiling point of solution (solid) decreases by `0.68^(@)C`, atomicity of sulphur is
(`K_(f)` of naphthalene=6.8 `Km^(-1)`)

A

2

B

4

C

6

D

8

Text Solution

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The correct Answer is:
To solve the problem step by step, we will use the formula for the elevation of boiling point and the information provided in the question. ### Step 1: Write down the formula for boiling point elevation The formula for boiling point elevation is given by: \[ \Delta T_b = K_b \cdot m \] where: - \(\Delta T_b\) = elevation in boiling point - \(K_b\) = ebullioscopic constant of the solvent (naphthalene in this case) - \(m\) = molality of the solution ### Step 2: Identify the known values From the question, we have: - \(\Delta T_b = 0.68°C\) - \(K_b = 6.8 \, \text{K kg}^{-1}\) - Mass of naphthalene (solvent) = 100 g = 0.1 kg - Mass of sulfur (solute) = 2.56 g ### Step 3: Calculate the molality of the solution Rearranging the boiling point elevation formula to find molality: \[ m = \frac{\Delta T_b}{K_b} \] Substituting the known values: \[ m = \frac{0.68}{6.8} = 0.1 \, \text{mol/kg} \] ### Step 4: Use the definition of molality Molality is defined as: \[ m = \frac{n}{W} \] where: - \(n\) = number of moles of solute - \(W\) = mass of solvent in kg From the previous calculation, we have: \[ 0.1 = \frac{n}{0.1} \implies n = 0.1 \times 0.1 = 0.01 \, \text{mol} \] ### Step 5: Calculate the molar mass of sulfur The number of moles \(n\) can also be expressed as: \[ n = \frac{m_{\text{solute}}}{M_{\text{solute}}} \] where \(m_{\text{solute}} = 2.56 \, \text{g}\) and \(M_{\text{solute}}\) is the molar mass of sulfur. Rearranging gives: \[ M_{\text{solute}} = \frac{m_{\text{solute}}}{n} = \frac{2.56 \, \text{g}}{0.01 \, \text{mol}} = 256 \, \text{g/mol} \] ### Step 6: Determine the atomicity of sulfur The molar mass of sulfur is approximately \(32 \, \text{g/mol}\). The atomicity \(x\) can be calculated as: \[ M_{\text{solute}} = 32x \implies 256 = 32x \implies x = \frac{256}{32} = 8 \] ### Conclusion The atomicity of sulfur is 8.
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