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Osmotic pressure of a 0.01 M solution is...

Osmotic pressure of a 0.01 M solution is 0.7 atm at `27^(@)C`, its van't Hoff factor will be

A

2.76

B

2.7

C

2.84

D

2.6

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The correct Answer is:
To find the van't Hoff factor (i) for the given solution, we can use the formula for osmotic pressure: \[ \pi = iCRT \] Where: - \(\pi\) = osmotic pressure (in atm) - \(i\) = van't Hoff factor - \(C\) = concentration of the solution (in molarity) - \(R\) = universal gas constant (0.0821 atm L/mol K) - \(T\) = temperature (in Kelvin) ### Step-by-Step Solution: 1. **Identify Given Values**: - Osmotic pressure, \(\pi = 0.7 \, \text{atm}\) - Concentration, \(C = 0.01 \, \text{M}\) - Temperature, \(T = 27^\circ C\) 2. **Convert Temperature to Kelvin**: \[ T(K) = 273 + 27 = 300 \, K \] 3. **Substitute Values into the Osmotic Pressure Formula**: \[ 0.7 = i \times 0.01 \times 0.0821 \times 300 \] 4. **Calculate the Right Side**: First, calculate \(0.01 \times 0.0821 \times 300\): \[ 0.01 \times 0.0821 = 0.000821 \] \[ 0.000821 \times 300 = 0.2463 \] 5. **Rearrange the Equation to Solve for \(i\)**: \[ i = \frac{0.7}{0.2463} \] 6. **Calculate \(i\)**: \[ i \approx 2.84 \] ### Final Answer: The van't Hoff factor \(i\) is approximately **2.84**. ---
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