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A' gram of non-volatile, non-electrolyte...

A' gram of non-volatile, non-electrolyte (molar mass M) is dissolved in 200 ml of unknown solvent (density`=1.25 gm//ml` molal elevation constant is `K_(b)`) .Elevation in boiling point of this solution can be given by

A

`(M)/(K_(b))`

B

`(4K_(b)A)/(M)`

C

`(K_(b)A)/(4M)`

D

`(K_(b)M)/(4A)`

Text Solution

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The correct Answer is:
To solve the problem of determining the elevation in boiling point (\( \Delta T_b \)) of a solution made by dissolving \( A \) grams of a non-volatile, non-electrolyte solute with molar mass \( M \) in 200 ml of an unknown solvent (with a density of 1.25 g/ml), we can follow these steps: ### Step 1: Calculate the mass of the solvent The mass of the solvent can be calculated using the formula: \[ \text{Mass of solvent} = \text{Volume} \times \text{Density} \] Given that the volume of the solvent is 200 ml and the density is 1.25 g/ml, we can substitute these values: \[ \text{Mass of solvent} = 200 \, \text{ml} \times 1.25 \, \text{g/ml} = 250 \, \text{g} \] ### Step 2: Convert the mass of the solvent to kilograms Since molality is defined in terms of kilograms of solvent, we convert the mass of the solvent from grams to kilograms: \[ \text{Mass of solvent in kg} = \frac{250 \, \text{g}}{1000} = 0.25 \, \text{kg} \] ### Step 3: Calculate the number of moles of solute The number of moles of solute can be calculated using the formula: \[ \text{Moles of solute} = \frac{\text{Mass of solute}}{\text{Molar mass of solute}} = \frac{A}{M} \] ### Step 4: Calculate the molality of the solution Molality (\( m \)) is defined as the number of moles of solute per kilogram of solvent: \[ m = \frac{\text{Moles of solute}}{\text{Mass of solvent in kg}} = \frac{A/M}{0.25} \] This simplifies to: \[ m = \frac{4A}{M} \] ### Step 5: Use the formula for elevation in boiling point The elevation in boiling point can be calculated using the formula: \[ \Delta T_b = K_b \times m \] Substituting the expression for molality: \[ \Delta T_b = K_b \times \frac{4A}{M} \] ### Final Answer Thus, the elevation in boiling point of the solution can be given by: \[ \Delta T_b = \frac{4K_b A}{M} \]
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