STATEMENT-1 : For solution of volatile liquids, the partial vapour pressure of each component in the solution is directly proportional to its mole fraction.
STATEMENT-2 : Always there will be lowering of vapour pressure on addition of non-volatile solute to a solvent.
STATEMENT-3 : If there is dissociation of non-volatile then the V.P. of solution increases.

Options

A. T F T
B. F F T
C. T T F
D. F T F

Answer

To analyze the statements provided in the question, we will evaluate each statement one by one, using principles from chemistry, particularly Raoult's law and the behavior of solutions.

### Step-by-step Solution:

**Step 1: Evaluate Statement 1**
- **Statement 1**: "For solution of volatile liquids, the partial vapor pressure of each component in the solution is directly proportional to its mole fraction."
- According to Raoult's law, the partial vapor pressure (P) of a component in a solution is given by the equation:
\[ P_i = P_i^0 \cdot x_i \]
where \(P_i^0\) is the vapor pressure of the pure component and \(x_i\) is the mole fraction of the component in the solution. This shows that the partial vapor pressure is indeed directly proportional to the mole fraction.
- **Conclusion**: Statement 1 is **True**.

**Step 2: Evaluate Statement 2**
- **Statement 2**: "Always there will be lowering of vapor pressure on addition of non-volatile solute to a solvent."
- A non-volatile solute does not have a vapor pressure of its own. When a non-volatile solute is added to a solvent, it occupies space at the surface of the liquid, which reduces the number of solvent molecules that can escape into the vapor phase. This results in a decrease in the vapor pressure of the solvent.
- **Conclusion**: Statement 2 is **True**.

**Step 3: Evaluate Statement 3**
- **Statement 3**: "If there is dissociation of non-volatile then the vapor pressure of solution increases."
- When a non-volatile solute dissociates (for example, an ionic compound dissolving in water), it produces more particles in solution. However, since non-volatile solutes do not contribute to vapor pressure, the overall effect is still a lowering of vapor pressure. The presence of more solute particles (due to dissociation) leads to an even greater reduction in vapor pressure compared to a non-dissociating solute.
- **Conclusion**: Statement 3 is **False**.

### Final Conclusion:
- Statement 1: True
- Statement 2: True
- Statement 3: False

Thus, the correct option is that Statement 1 is true, Statement 2 is true, and Statement 3 is false.