Conductivity of 0.12 M `CuSO_(4)` solution at 298 K is `1.8 xx 10^(-2) S cm^(-1)` Calculate its equivalent conductivity

Explanation

To calculate the equivalent conductivity of a 0.12 M `CuSO4` solution at 298 K, we can follow these steps:

### Step 1: Understand the given data
- Molarity (C) of `CuSO4` = 0.12 M
- Conductivity (K) of the solution = `1.8 x 10^(-2) S cm^(-1)`

### Step 2: Determine the normality of the solution
Normality (N) is calculated using the formula:
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