Molar conductivity of a weak acid HA at infinite dilution is 345.8 `cm^(2) mol^(-)` calculate molar conductivity of 0.05 M HA solution `(alpha=5.8` x `10^(-6))`

Explanation

To solve the problem of calculating the molar conductivity of a 0.05 M solution of the weak acid HA, we can follow these steps:

### Step 1: Understand the given data
We are provided with:
- Molar conductivity of HA at infinite dilution (λ_m^∞) = 345.8 cm² mol⁻¹
- Degree of dissociation (α) = 5.8 x 10⁻⁶
- Concentration of the solution (C) = 0.05 M

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