Calculate molar conductivity of `CH_(3)COOH` at infinit e dilution if `A_(m)^(@)` for NACI,HCI and `CH_(3)COONA` are 126.45,426.16 an 91 S `cm(^2) mol^(-1)` respectively The molar conductivity of CH 3 ​ COOH at infinite dilution is 390.71 Scm (^)2 mol −1 .

Explanation

To calculate the molar conductivity of acetic acid (CH₃COOH) at infinite dilution, we can use the provided molar conductivities of NaCl, HCl, and CH₃COONa. The molar conductivities of the ions can be combined to find the molar conductivity of acetic acid.

### Step-by-Step Solution:

1. **Identify the given values:**
- Molar conductivity of NaCl (λM0(NaCl)) = 126.45 S cm² mol⁻¹
- Molar conductivity of HCl (λM0(HCl)) = 426.16 S cm² mol⁻¹
- Molar conductivity of CH₃COONa (λM0(CH₃COONa)) = 91 S cm² mol⁻¹
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