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Calculate the Delta G^(@) and equilibriu...

Calculate the `Delta G^(@)` and equilibrium constant of the rectoi at `27^(@)C`
`Mg+Cu^(+2)- Mg^(+2)+Cu`
`E_(Mg^(2+)//Mg)^(@)=-2.37 V`
`E_(Cu^(2+)//Cu)^(@)=+0.34V`

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AI Generated Solution

To solve the problem of calculating ΔG° and the equilibrium constant for the reaction: \[ \text{Mg} + \text{Cu}^{2+} \rightarrow \text{Mg}^{2+} + \text{Cu} \] at \( 27^\circ C \), we will follow these steps: ### Step 1: Identify the standard reduction potentials From the problem, we have the following standard reduction potentials: ...
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Calculate the DeltaG^(@) and equilibrium constant of the reaction at 27^(@)C Mg+ Cu^(+2) hArr Mg^(+2) + Cu E_(Mg^(2+)//Mg)^(@) = -2.37V, E_(Cu^(2+)//Cu)^(@) = +0.34V

Calculate the equilibrium constant for the reaction at 298 K Zn(s)+Cu^(2+)(aq)harr Zn^(2+)(aq)+Cu(s) Given " " E_(Zn^(2+)//Zn)^(@)=-0.76 V and E_(Cu^(2+)//Cu)^(@)=+0.34 V

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

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The equilibrium constant for the cell Cu(s)+2Ag^+(aq)rarrCu^(2+)(aq)+2Ag(s) ,at 298K is [Given, E_((Ag)^+/(Ag))^o=0.8V and E_((Cu)^(2+)/(Cu))^o=0.34V ]

Find the equilibrium constant for the reaction Cu^(2+)+ 1n^(2+) Cu^(+) + 1n^(3+) Given that E_(CU^(2+)//CU^(+))^(@) = 0.15V, E_(In^(2+)//1n^(+)) = -0.4V E_(1n^(3+)//1n^(+))^(@) = - 0.42V

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