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The resistacnce of a conductivity cell f...

The resistacnce of a conductivity cell filled with 0.01 N KCI at `25^(@)C` was found to be 500 `Omega` The specific conductance of 0.01 N KCI at `25^(@)C` is `1.41xx10^(-3) Omega^(-) cm^(-1)` The resistance of same cell filled with `0.3 N ZnSO_(4)` at `25^(@)C` was found to be 69 `Omega` Calculate the cell constant equivalent and molar conductivities of `ZnSO_(4)` solution

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To solve the problem step by step, we will calculate the cell constant, equivalent conductivity, and molar conductivity of the ZnSO₄ solution. ### Step 1: Calculate the Cell Constant (G*) The formula relating specific conductance (κ), conductance (G), and cell constant (G*) is given by: \[ \kappa = G \times G^* ...
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