STATEMENT-1: Zeise's salt contain `C_(2)H_(4)` molecule as one of the ligands
and
STATEMENT-2: Zeise's salt is an organometallic compound .

Options

A. Statement-1 is True , Statement-2 is True , Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True , Statement-2 is True , Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True , Statement-2 is False
D. Statement-1 is False , Statement-2 is True

Answer

To analyze the statements regarding Zeise's salt, we will break down each statement step by step.

### Step 1: Analyze Statement 1
**Statement 1:** Zeise's salt contains \( C_2H_4 \) molecule as one of the ligands.

- **Explanation:** Zeise's salt is known to be a coordination compound with the formula \( K[PtCl_3(C_2H_4)] \). In this formula, \( C_2H_4 \) (ethylene) acts as a ligand that coordinates to the platinum (Pt) center. Therefore, Statement 1 is **true**.

### Step 2: Analyze Statement 2
**Statement 2:** Zeise's salt is an organometallic compound.

- **Explanation:** Organometallic compounds are defined as compounds that contain a metal atom bonded to a carbon atom of an organic molecule. Since Zeise's salt contains platinum (a metal) bonded to ethylene (an organic ligand), it qualifies as an organometallic compound. Thus, Statement 2 is also **true**.

### Step 3: Determine the Relationship Between the Statements
- While both statements are true, we need to check if Statement 2 provides a correct explanation for Statement 1.
- Statement 1 identifies the presence of \( C_2H_4 \) as a ligand, while Statement 2 categorizes Zeise's salt as an organometallic compound. However, Statement 2 does not directly explain why \( C_2H_4 \) is a ligand in Zeise's salt; it simply states a classification.

### Conclusion
- **Final Assessment:**
- Statement 1 is true.
- Statement 2 is true.
- Statement 2 is not a correct explanation of Statement 1.

Thus, the correct answer is that both statements are true, but Statement 2 does not explain Statement 1.