STATEMENT-1: `Fe(CO)_(5)` has trigonal bipyramidal shape .
and
STATEMENT-2: `Fe(CO)_(5)` is diamagnetic

Options

A. Statement-1 is True , Statement-2 is True , Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True , Statement-2 is True , Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True , Statement-2 is False
D. Statement-1 is False , Statement-2 is True

Answer

To analyze the statements regarding `Fe(CO)_(5)`, we will break down the solution into clear steps.

### Step 1: Determine the Oxidation State of Iron in `Fe(CO)_(5)`

1. **Identify the ligands**: Carbon monoxide (CO) is a neutral ligand, meaning it does not contribute any charge.
2. **Calculate the oxidation state**: Since the overall charge of the complex is zero and CO is neutral, the oxidation state of iron (Fe) must also be zero.

**Hint**: Remember that the oxidation state of a neutral ligand is zero.

### Step 2: Write the Electronic Configuration of Iron

1. **Find the atomic number of Fe**: Iron has an atomic number of 26.
2. **Write the electronic configuration**: The electronic configuration of Fe is `Ar 3d^6 4s^2`.

**Hint**: Use the periodic table to find the atomic number and then write the configuration based on the order of filling.

### Step 3: Analyze the Hybridization

1. **Consider the strong field ligand**: CO is a strong field ligand, which causes pairing of electrons in the d-orbitals.
2. **Pair the electrons**: In the presence of CO, the 3d electrons will pair up, leading to the configuration:
- 3d: 1, 2, 3, 4, 5, 6 (all paired)
- 4s: 2 (also paired)
3. **Determine the hybridization**: The hybridization for `Fe(CO)_(5)` is `dsp^3`, which corresponds to trigonal bipyramidal geometry.

**Hint**: Strong field ligands can cause pairing of electrons, which affects the hybridization.

### Step 4: Determine the Shape of `Fe(CO)_(5)`

1. **Identify the hybridization shape**: The `dsp^3` hybridization corresponds to a trigonal bipyramidal shape.
2. **Conclude about Statement 1**: Therefore, Statement 1 is true.

**Hint**: Recall the common geometries associated with different types of hybridization.

### Step 5: Check for Magnetic Properties

1. **Count the unpaired electrons**: After pairing, there are no unpaired electrons in `Fe(CO)_(5)`.
2. **Determine if it is diamagnetic**: Since there are no unpaired electrons, `Fe(CO)_(5)` is diamagnetic.

**Hint**: A compound is diamagnetic if it has no unpaired electrons.

### Conclusion

- **Statement 1**: `Fe(CO)_(5)` has a trigonal bipyramidal shape - **True**.
- **Statement 2**: `Fe(CO)_(5)` is diamagnetic - **True**.

However, Statement 2 does not explain Statement 1, so the correct option is that both statements are true, but Statement 2 is not a correct explanation of Statement 1.

### Final Answer

Both statements are true, but Statement 2 is not a correct explanation of Statement 1.