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FeSO4 solution mixed with (NH4)2SO4 solu...

`FeSO_4` solution mixed with `(NH_4)_2SO_4` solution is `1:1` molar ratio gives the test of `Fe^(2+)` ion but `CuSO_4` solution mixed with aqueous ammonia in `1:4` molar ratio does not give the test of `Cu^(2+)` ion. Explain why?

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To understand why the test for \( \text{Fe}^{2+} \) ions is positive when mixing \( \text{FeSO}_4 \) with \( (NH_4)_2SO_4 \) in a 1:1 molar ratio, while the test for \( \text{Cu}^{2+} \) ions is negative when mixing \( \text{CuSO}_4 \) with aqueous ammonia in a 1:4 molar ratio, we can break down the explanation into several steps: ### Step-by-Step Solution: 1. **Understanding the Reaction of \( \text{FeSO}_4 \) and \( (NH_4)_2SO_4 \)**: - When \( \text{FeSO}_4 \) is mixed with \( (NH_4)_2SO_4 \), they form a double salt known as Mohr's salt, represented as \( \text{FeSO}_4 \cdot (NH_4)_2SO_4 \cdot 6H_2O \). - This compound is stable in solid form, and when dissolved in water, it dissociates into its constituent ions: \( \text{Fe}^{2+} \), \( \text{NH}_4^{+} \), and \( \text{SO}_4^{2-} \). ...
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