Home
Class 12
CHEMISTRY
How many of the given species will behav...

How many of the given species will behave as an electrophile?
`:C Cl_(2),NH_(3),overset(o+)(CH_(3)),overset(o+)(NH_(4)),overset(-)(CH_(3)),overset(-)(OH),BF_(3),AlCl_(3),overset(o+)(Br)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine how many of the given species behave as electrophiles, we need to analyze each species based on its electron density and charge. Electrophiles are defined as electron-deficient species that can accept electrons from nucleophiles. ### Step-by-Step Solution: 1. **CCl₂ (Chlorocarbene)**: - Chlorocarbene has two chlorine atoms attached to a carbon atom that has only 6 electrons in its valence shell (due to the two bonds with chlorine). - **Conclusion**: CCl₂ is electron deficient and behaves as an electrophile. 2. **NH₃ (Ammonia)**: - Ammonia has a lone pair of electrons on the nitrogen atom, making it electron-rich. - **Conclusion**: NH₃ does not behave as an electrophile. 3. **CH₃⁺ (Methyl cation)**: - The methyl cation has a positive charge and only 6 electrons around the carbon atom, indicating it is electron deficient. - **Conclusion**: CH₃⁺ is an electrophile. 4. **NH₄⁺ (Ammonium ion)**: - The ammonium ion has a complete octet with four hydrogen atoms bonded to nitrogen, making it stable and electron-rich. - **Conclusion**: NH₄⁺ does not behave as an electrophile. 5. **CH₃⁻ (Methyl anion)**: - The methyl anion has a negative charge and 8 electrons around the carbon atom, indicating it is electron-rich. - **Conclusion**: CH₃⁻ does not behave as an electrophile. 6. **OH⁻ (Hydroxide ion)**: - The hydroxide ion has a negative charge and a lone pair of electrons, making it electron-rich. - **Conclusion**: OH⁻ does not behave as an electrophile. 7. **BF₃ (Boron trifluoride)**: - Boron trifluoride has an incomplete octet (only 6 electrons), making it electron deficient and capable of accepting electrons. - **Conclusion**: BF₃ is an electrophile. 8. **AlCl₃ (Aluminum chloride)**: - Aluminum chloride also has an incomplete octet (only 6 electrons) and can accept electrons. - **Conclusion**: AlCl₃ is an electrophile. 9. **Br⁺ (Bromonium ion)**: - The bromonium ion has a positive charge, indicating it is electron deficient. - **Conclusion**: Br⁺ is an electrophile. ### Summary of Electrophilic Species: - Electrophiles: CCl₂, CH₃⁺, BF₃, AlCl₃, Br⁺ - Non-electrophiles: NH₃, NH₄⁺, CH₃⁻, OH⁻ ### Total Count of Electrophiles: There are **5 species** that behave as electrophiles. ---
Promotional Banner

Topper's Solved these Questions

  • ORGANIC CHEMISTRY: SOME BASIC PRINCIPLE AND TECHNIQUES

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-H MULTIPLE TRUE-FALSE TYPE QUESTION|2 Videos
  • ORGANIC CHEMISTRY: SOME BASIC PRINCIPLE AND TECHNIQUES

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-I SUBJECTIVE TYPE QUESTIONS|8 Videos
  • ORGANIC CHEMISTRY: SOME BASIC PRINCIPLE AND TECHNIQUES

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-F MATRIX-MATCH TYPE QUESTIONS|4 Videos
  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment(Section-D)(Assertion - Reason Type Questions)|15 Videos
  • POLYMERS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION-D)|13 Videos

Similar Questions

Explore conceptually related problems

CH_(3)-overset(O)overset(||)C-CH_(3)overset(SeO_(2))rarrA,A is :

Arrange nucleophilicity of given species in decreasing order: (1) CH_(3)-overset(ө)CH_(2) (2) CH_(3)-overset(ө)O (3) overset(ө)NH_(2) (4) overset(ө)F

The IUPAC name of CH_(3)-overset(O)overset(||)(C)-CH_(2)-overset(OH)overset(|)(CH)-CHO is

The IUPAC name of CH_(3)-overset(O)overset(||)(C)-CH_(2)-overset(OH)overset(|)(CH)-CHO is

Which of the following are isoelectronic species ? overset(o+)(CH_(3))(I), overset(ɵ)(NH_(2))(II), overset(o+)(NH_(4))(III) and NH_(3) (IV)

CH_3-overset(OH)overset(|)(CH)-overset(O)overset(||)(C )-CH_2 - CH_(3) will respond to

CH_(3)-CH_(2)-CH_(2)-O-CH_(3) and CH_(3)-overset(CH_(3))overset(|)(C )H-O-CH_(3) are

The IUPAC name for CH_(3)-overset(O)overset(||)(C)-CH_(2)-CH_(2)-overset(O)overset(||)(C)-OH is ______.