How many total types of products are formed by dehydrohalogenation of 2 chlorobutane?

Answer

To determine how many total types of products are formed by the dehydrohalogenation of 2-chlorobutane, we can follow these steps:

### Step 1: Understand the Structure of 2-Chlorobutane
2-Chlorobutane has the following structure:
- CH3-CH(Cl)-CH2-CH3

### Step 2: Identify the Dehydrohalogenation Process
Dehydrohalogenation involves the elimination of a hydrogen atom and a halogen atom (in this case, chlorine) from adjacent carbon atoms, leading to the formation of alkenes.

### Step 3: Identify Beta Hydrogens
In 2-chlorobutane, the carbon attached to the chlorine (the alpha carbon) is connected to two beta carbons. The beta carbons have hydrogen atoms that can be eliminated:
- Beta positions are the carbons adjacent to the alpha carbon (the one with Cl).

### Step 4: Possible Products from Beta Hydrogen Elimination
1. **Elimination of a beta hydrogen from the first beta carbon (CH2):**
- This will lead to the formation of:
- CH2=CH-CH2-CH3 (But-1-ene)

2. **Elimination of a beta hydrogen from the second beta carbon (CH3):**
- This will lead to the formation of:
- CH3-CH=CH-CH3 (But-2-ene)

### Step 5: Identify Geometric Isomers
For the product But-2-ene, it can exist in two geometric forms:
- **Cis-But-2-ene:** where the two methyl groups (CH3) are on the same side of the double bond.
- **Trans-But-2-ene:** where the two methyl groups (CH3) are on opposite sides of the double bond.

### Step 6: Count the Total Types of Products
- From the elimination of beta hydrogen from the first beta carbon, we have:
- 1 product: But-1-ene
- From the elimination of beta hydrogen from the second beta carbon, we have:
- 2 products: Cis-But-2-ene and Trans-But-2-ene

### Final Count of Products
- Total products = 1 (But-1-ene) + 2 (Cis and Trans But-2-ene) = **3 types of products.**

### Conclusion
The total number of different types of products formed by the dehydrohalogenation of 2-chlorobutane is **3**.

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