When an alkyl chloride is treated with Na in dry ether, a symmetrical alkane is obtained. The reaction is known as

Options

A. Birch redcuction
B. Frankland reaction
C. Wurtz reaction
D. Halogenation reaction.

Answer

To solve the question, we need to identify the reaction that occurs when an alkyl chloride is treated with sodium in dry ether, resulting in the formation of a symmetrical alkane. Let's break down the solution step by step.

### Step-by-Step Solution:

1. **Understanding the Reactants and Conditions**:
- We have an alkyl chloride (RX) as the starting material.
- The reaction is carried out in the presence of sodium (Na) and dry ether as the solvent.

2. **Identifying the Reaction Type**:
- The question states that a symmetrical alkane is formed. This suggests a coupling reaction where two alkyl radicals combine.

3. **Reviewing the Given Options**:
- **Birch Reduction**: This reaction involves the reduction of benzene using sodium and ammonia in the presence of alcohol, which does not apply here.
- **Franklin Reaction**: This involves the reaction of two moles of alkyl chloride with zinc, which is not relevant since we are using sodium.
- **Wood’s Reaction**: This reaction involves the treatment of two moles of alkyl halide with sodium in dry ether, leading to the formation of a symmetrical alkane and sodium halide.
- **Halogenation Reaction**: This involves the addition of halogens to alkenes, which is not applicable in this case.

4. **Choosing the Correct Option**:
- Among the options, Wood's reaction is the only one that matches the conditions described in the question. It involves the coupling of two alkyl radicals to form a symmetrical alkane.

5. **Conclusion**:
- Therefore, the correct answer is **Wood's Reaction**.

### Final Answer:
The reaction when an alkyl chloride is treated with sodium in dry ether to obtain a symmetrical alkane is known as **Wood's Reaction**.