How many `sigma`-bonds and `pi-`bonds are present in the given compound?
`CH_(3)-CH_(2)-CH=CH-C-=CH`

Options

A. `sigma-14, pi-5`
B. `sigma-12 , pi-1`
C. `sigma-13 , pi-3`
D. `sigma-14 , pi-3`

Answer

To determine the number of sigma (σ) and pi (π) bonds in the compound `CH₃-CH₂-CH=CH-C≡CH`, we will analyze the structure step by step.

### Step 1: Draw the structure
The compound can be drawn as follows:
```
H H H H
| | | |
H--C---C===C---C≡C---H
| | | |
H H H H
```
This structure indicates the connectivity of the carbon and hydrogen atoms.

### Step 2: Identify the types of bonds
- **Single bonds** (σ bonds): These are formed between carbon atoms and between carbon and hydrogen atoms.
- **Double bonds**: Each double bond consists of one σ bond and one π bond.
- **Triple bonds**: Each triple bond consists of one σ bond and two π bonds.

### Step 3: Count the σ bonds
1. Between `C1` and `C2`: 1 σ bond
2. Between `C2` and `C3`: 1 σ bond
3. Between `C3` and `C4`: 1 σ bond (part of the double bond)
4. Between `C4` and `C5`: 1 σ bond (part of the triple bond)
5. Between `C5` and `C6`: 1 σ bond (part of the triple bond)
6. Between `C1` and `H`: 3 σ bonds (3 H atoms attached to `C1`)
7. Between `C2` and `H`: 2 σ bonds (2 H atoms attached to `C2`)
8. Between `C3` and `H`: 1 σ bond (1 H atom attached to `C3`)
9. Between `C4` and `H`: 1 σ bond (1 H atom attached to `C4`)
10. Between `C5` and `H`: 1 σ bond (1 H atom attached to `C5`)

Now, let's count them:
- Total σ bonds from C-C: 5 (1 + 1 + 1 + 1 + 1)
- Total σ bonds from C-H: 8 (3 + 2 + 1 + 1 + 1)

Total σ bonds = 5 + 8 = **13 σ bonds**.

### Step 4: Count the π bonds
- The double bond between `C3` and `C4` contributes **1 π bond**.
- The triple bond between `C4` and `C5` contributes **2 π bonds**.

Total π bonds = 1 + 2 = **3 π bonds**.

### Final Count
- **Total σ bonds** = 13
- **Total π bonds** = 3

### Conclusion
The compound `CH₃-CH₂-CH=CH-C≡CH` contains **13 sigma bonds** and **3 pi bonds**.

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