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(A)overset(Alc. KOH)rarrCH(3)-CH=CH(2)un...

(A)`overset(Alc. KOH)rarrCH_(3)-CH=CH_(2)underset(("Peroxide"))overset(HBr)rarr(B)` Find the product (A) and (B) in the given reaction

A

`CH_(3)-underset(Br)underset(|)(CH)-CH_(3),CH_(3)-CH_(2)-CH_(2)-Br`

B

`CH_(3)-CH-CH_(2)-Br,CH_(3)-underset(Br)underset(|)(CH)-CH_(3)`

C

`Br-CH_(2)-CH=CH_(2),CH_(3)-CH=CH-Br`

D

`underset(Br)underset(|)(CH_(2))-CH=CH_(2),CH_(3)-underset(Br)underset(|)(C)=CH_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to identify the reactants and products in the given reactions. Let's break it down step by step. ### Step 1: Identify Product A The reaction starts with a compound A that reacts with alcoholic KOH. Alcoholic KOH is known to facilitate elimination reactions, leading to the formation of alkenes. Given the options, we need to determine which compound can yield the alkene CH3-CH=CH2 upon treatment with alcoholic KOH. 1. **Option A:** CH3-CHBr-CH3 - When treated with alcoholic KOH, bromine (Br) is eliminated along with a hydrogen atom from the adjacent carbon, resulting in CH3-CH=CH2. - This matches our desired alkene. 2. **Option B:** CH3-CH-CH2Br - Similarly, treating this compound with alcoholic KOH will also lead to the formation of CH3-CH=CH2 through elimination. Both options A and B can yield the same alkene, CH3-CH=CH2. ### Step 2: Identify Product B Next, we need to determine the product B formed when the alkene CH3-CH=CH2 is treated with HBr in the presence of peroxide. According to the anti-Markovnikov rule, the addition of HBr in the presence of peroxide results in the hydrogen atom attaching to the carbon with fewer hydrogen atoms (the terminal carbon), while the bromine attaches to the carbon with more hydrogen atoms. - The alkene CH3-CH=CH2 will react as follows: - H will add to the first carbon (CH2) and Br will add to the second carbon (CH). Thus, the product B is CH3-CH2-CH2Br. ### Conclusion - **Product A:** CH3-CHBr-CH3 (or CH3-CH-CH2Br) - **Product B:** CH3-CH2-CH2Br ### Final Answer - Product A is CH3-CHBr-CH3 (or CH3-CH-CH2Br). - Product B is CH3-CH2-CH2Br.
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Knowledge Check

  • Supply structural formulae for missing compounds. (i) H_(2)C=CH_(2)+(A) rarr ClCH_(2)-CH_(2)OH underset(413K)overset(H_(2)SO_(4))(rarr) (B) underset(Delta)overset("alc. KOH")(rarr) (C ) (ii) CH_(3)CHBrCH_(3)overset("alc. KOH")(rarr)(A)underset("Peroxide")overset(HBr)(rarr)(B)overset(CH_(3)ONa)(rarr)(C ) (iii) Me_(3)CBroverset("alc. KOH")(rarr)(A) overset(HOCl)(rarr) (B) overset(NaOH)(rarr)(C )

    A
    `{:(A,B,C),(CH_3CH=CH_2,CH_3CH(Br)CH_2Br,CH_3CH(OH)CH_3):}`
    B
    `{:(A,B,C),(CH_3CH=CH_2 ,CH_3CH_2CH_2 Br,CH_3CH_2OCH_2CH_2):}`
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  • CH_(3)-overset(CH_(3))overset(|)(CH)-C-=CH overset("excess HBr")rarr The product of the above reaction is :

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    C
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    D
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