3-Hexyne reacts with Na/liq. `NH_(3)` to produce

Options

A. cis-3-Hexene
B. trans-3-Hexene
C. 3-Hexylamine
D. 2-Hexylamine

Answer

To solve the problem, we need to analyze the reaction of 3-Hexyne with sodium in liquid ammonia (Na/NH₃). Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Structure of 3-Hexyne
3-Hexyne is an alkyne with the molecular formula C₆H₁₀. The structure can be represented as follows:

- The carbon chain consists of six carbon atoms.
- The triple bond is located between the third and fourth carbon atoms.

The structure can be drawn as:
```
CH₃-CH₂-C≡C-CH₂-CH₃
```

### Step 2: Understand the Reaction Conditions
The reaction involves sodium (Na) and liquid ammonia (NH₃). This combination is known to facilitate a reaction called catalytic hydrogenation, which is used to convert alkynes to alkenes.

### Step 3: Reaction Mechanism
In the presence of sodium and liquid ammonia, the triple bond (C≡C) in 3-Hexyne is reduced to a double bond (C=C). This process typically leads to the formation of a trans alkene.

### Step 4: Determine the Product
After the reduction of 3-Hexyne, the product formed will be a double bond between the third and fourth carbon atoms. Since the reaction favors the formation of the trans isomer, the resulting product will be trans-3-hexene.

The structure of trans-3-hexene can be represented as:
```
CH₃-CH₂-CH=CH-CH₂-CH₃
```
Where the substituents on either side of the double bond are on opposite sides, confirming it is a trans isomer.

### Step 5: Conclusion
The product of the reaction between 3-Hexyne and sodium in liquid ammonia is trans-3-hexene.

### Final Answer
The correct answer is **trans-3-hexene**.