Colouration of `Br_(2)//C Cl_(4)` will be discharged by

Options

A.
B.
C.
D.

Answer

To solve the question regarding which compound will discharge the coloration of Br₂/CCl₄, we need to analyze the options given and understand the reactivity of each compound with bromine in the presence of carbon tetrachloride (CCl₄).

### Step-by-Step Solution:

1. **Understanding Br₂/CCl₄**:
- Br₂ in carbon tetrachloride is a brown solution. This solution is used to test for unsaturation (double or triple bonds) in organic compounds. When an unsaturated compound reacts with Br₂, the brown color of the solution is discharged.

2. **Analyzing the Options**:
- **Option 1: Cinnamic Acid (CH₂=CH-COOH)**:
- Cinnamic acid contains a double bond (C=C) between the two carbon atoms. When it reacts with Br₂ in CCl₄, the double bond will react with bromine, resulting in the formation of dibromocinnamic acid. This reaction will discharge the brown color of the Br₂ solution.
- **Conclusion**: This option will discharge the color.

- **Option 2: Benzoic Acid (C6H5COOH)**:
- Benzoic acid does not have any double or triple bonds that can react with Br₂ in CCl₄. The reaction of bromine with benzoic acid typically requires a Lewis acid catalyst like AlCl₃. Therefore, there will be no discharge of color.
- **Conclusion**: This option will not discharge the color.

- **Option 3: Phthalic Acid (C6H4(COOH)₂)**:
- Similar to benzoic acid, phthalic acid also does not have a double bond that can react with Br₂ in CCl₄. It requires AlCl₃ for bromination. Thus, there will be no discharge of color.
- **Conclusion**: This option will not discharge the color.

- **Option 4: Acetophenone (C6H5C(O)CH₃)**:
- Acetophenone has a ketone group, which does not participate in the reaction with bromine in CCl₄. Therefore, there will be no discharge of color.
- **Conclusion**: This option will not discharge the color.

3. **Final Answer**:
- The only compound that will discharge the coloration of Br₂/CCl₄ is **Cinnamic Acid** (Option 1).