`underset(Br)underset(|)(CH_(2))-CH=CH-underset(Br)underset(|)(CH_(2))overset(Zn / CH_(3)OH)rarr` Product The predominating product is

Options

A.
B. `CH_(2)=C=C=CH_(2)`
C. `CH_(2)=CH-CH=CH_(2)`
D.

Answer

To solve the problem, we need to analyze the given compound and the reagents involved in the reaction.

### Step-by-Step Solution:

1. **Identify the Structure of the Compound**:
The compound provided is a 1,4-dibromobut-2-ene. Its structure can be represented as:
\[ \text{Br-CH}_2-\text{CH}=\text{CH-CH}_2-\text{Br} \]
Here, two bromine atoms are attached to the terminal carbon atoms of the butene chain.

2. **Understand the Reagents**:
The reagents given are zinc (Zn) and methanol (CH₃OH). Zinc is known to facilitate dehalogenation reactions, which means it can remove halogen atoms from organic compounds.

3. **Reaction Mechanism**:
- When zinc reacts with the dibromide, it will remove the two bromine atoms. This process is called dehalogenation.
- The removal of the bromine atoms leads to the formation of a double bond between the adjacent carbon atoms, resulting in the formation of a radical intermediate.

4. **Formation of the Product**:
- The radical intermediate can undergo a rearrangement or recombination to form a cyclic structure due to the proximity of the carbon atoms.
- Specifically, the two carbon atoms that were initially bonded to the bromines can form a cyclobutene structure as they come together to stabilize the radical.

5. **Final Product**:
The predominant product of the reaction is cyclobutene, which can be represented as:
\[ \text{C}_4\text{H}_6 \quad (\text{cyclobutene}) \]

### Conclusion:
The major product formed from the reaction of 1,4-dibromobut-2-ene with zinc in methanol is cyclobutene.

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