Statement-1: Ethyne is more reactive than ethene towards hydrogenation
Statement-2: `H_(2)` in presence of Lindlar catalyst is more reactive than `H_(2)` with Pd in hydrogenation reaction
Statement-3: Dipole moment of o-xylene is greater than m-xylene

Options

A. T F T
B. F T F
C. F F T
D. T T F

Answer

To analyze the statements provided in the question, we will evaluate each statement one by one and determine their truthfulness.

### Step 1: Evaluate Statement 1
**Statement 1:** Ethyne is more reactive than ethene towards hydrogenation.

**Analysis:**
- Ethyne (C2H2) is an alkyne, while ethene (C2H4) is an alkene.
- Alkynes are generally more reactive than alkenes due to the presence of a triple bond in alkynes, which can react with hydrogen more readily.
- However, in the context of hydrogenation, ethene is more reactive than ethyne because ethyne requires more hydrogen to saturate it fully, while ethene can be hydrogenated to form ethane more directly.

**Conclusion:** This statement is **false**.

### Step 2: Evaluate Statement 2
**Statement 2:** H2 in presence of Lindlar catalyst is more reactive than H2 with Pd in hydrogenation reaction.

**Analysis:**
- Lindlar's catalyst is a poisoned palladium catalyst that selectively hydrogenates alkynes to alkenes without further reducing the alkene to an alkane.
- The statement claims that H2 with Lindlar's catalyst is more reactive than H2 with Pd. However, Lindlar's catalyst is less reactive than palladium because it is designed to stop the reaction at the alkene stage.
- Therefore, the statement is incorrect.

**Conclusion:** This statement is **false**.

### Step 3: Evaluate Statement 3
**Statement 3:** Dipole moment of o-xylene is greater than m-xylene.

**Analysis:**
- Xylene has three isomers: ortho (o-xylene), meta (m-xylene), and para (p-xylene).
- In o-xylene, the two methyl groups are adjacent, which creates a net dipole moment due to the vector addition of the dipole moments of the C-H bonds.
- In m-xylene, the two methyl groups are separated by a carbon atom, leading to a lower net dipole moment than in o-xylene.
- Thus, o-xylene has a greater dipole moment than m-xylene.

**Conclusion:** This statement is **true**.

### Final Evaluation of Statements
- Statement 1: **False**
- Statement 2: **False**
- Statement 3: **True**

### Overall Conclusion
The correct option based on the evaluation of the statements is that Statement 3 is true while Statements 1 and 2 are false.

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