`CH_(3) -CH =CH_(2) + HOBr to P,` The major product P is

Options

A. `CH_(3)-underset(Br)underset(|)(CH)- underset(OH)underset(|)(CH_(2))`
B. `CH_(3) -underset(OH)underset(|)(CH) -underset(Br)underset(|)(CH_(2))`
C. `underset(Br)underset(|)(CH_(2)) -CH_(2) -underset(OH)underset(|)(CH_(2))`
D. `CH_(3)-overset(Br)overset(|)underset(OH)underset(|)(C )-CH_(3)`

Answer

To determine the major product P from the reaction of propene (CH₃-CH=CH₂) with HOBr, we will follow the steps of the electrophilic addition mechanism and apply Markovnikov's rule.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants are propene (CH₃-CH=CH₂) and HOBr.

2. **Understand the Electrophilic Addition Mechanism**:
In this reaction, HOBr acts as an electrophile. The bromine (Br) is the electrophilic part, and the hydroxyl group (OH) is the nucleophilic part.

3. **Apply Markovnikov's Rule**:
According to Markovnikov's rule, when HX (in this case, HOBr) adds to an alkene, the hydrogen (H) will attach to the carbon with more hydrogen atoms, while the halide (Br) will attach to the carbon with more alkyl substituents.

4. **Identify the Carbocation Formation**:
When the double bond in propene attacks the electrophile (Br⁺), a carbocation is formed. The double bond between the second and third carbon atoms can break, leading to the formation of a more stable carbocation. The more stable carbocation will be at the second carbon (C2), which has more hydrogen atoms.

- The structure of the carbocation will be CH₃-CH⁺-CH₂.

5. **Nucleophilic Attack**:
The hydroxyl ion (OH⁻) will then attack the carbocation. Since the carbocation is formed at the second carbon, the OH⁻ will attach to this carbon.

6. **Final Product Formation**:
The final product after the nucleophilic attack will be:
- CH₃-CHOH-CH₂Br.

Thus, the major product P formed from the reaction of propene with HOBr is **CH₃-CHOH-CH₂Br**.

### Conclusion:
The correct answer for the major product P is **CH₃-CHOH-CH₂Br**.

---