`CH_(3)-CH =CH_(2) overset(CI-I)(to) P,P `is

Options

A. `CH_(3) -underset(I)underset(|)(C H) -underset(CI)underset(|)(CH_(2))`
B. `CH_(3)-underset(CI)underset(|)(CH)-underset(I)underset(|)(CH_(2))`
C. `CH_(3)-overset(CI)overset(|)underset(I)underset(|)(C )- CH_(3)`
D.

Answer

To solve the problem, we need to analyze the reaction of propene (CH₃-CH=CH₂) with ClI and determine the product formed.

### Step-by-Step Solution:

1. **Identify the Reactants:**
The reactant is propene, which has the structure CH₃-CH=CH₂.

2. **Understand the Reaction Conditions:**
The reaction is carried out in the presence of ClI. In this compound, chlorine (Cl) is more electronegative than iodine (I). This means that during the reaction, Cl will act as a nucleophile and I will act as an electrophile.

3. **Electrophilic Addition Mechanism:**
When ClI interacts with the double bond in propene, the double bond will break, leading to the formation of a carbocation. The bond between the two carbon atoms will break, and the electrons will shift towards the more electronegative chlorine atom.

4. **Markovnikov's Rule:**
According to Markovnikov's rule, in the addition of HX (where X is a halogen) to an alkene, the halogen will attach to the more substituted carbon atom. In this case, the carbocation will form at the carbon with fewer hydrogens (the more substituted carbon).

5. **Formation of the Carbocation:**
The double bond in propene can be broken to form a secondary carbocation (CH₃-CH⁺-CH₂). The more stable carbocation will be formed at the second carbon (the one attached to CH₃).

6. **Nucleophilic Attack:**
The Cl⁻ ion (nucleophile) will attack the carbocation, leading to the formation of CH₃-CHCl-CH₂.

7. **Attack by Iodine:**
The remaining CH₂ group will then attack the I⁺ (electrophile) to form the final product.

8. **Final Product:**
The final product formed will be CH₃-CHCl-CH₂I.

### Conclusion:
The product P formed from the reaction of propene with ClI is CH₃-CHCl-CH₂I.

### Options Analysis:
- Option 1: CH₃-CHI-CH₂Cl (Incorrect)
- Option 2: CH₃-CHCl-CH₂I (Correct)
- Option 3: CH₃-CCL (Incorrect)
- Option 4: Incorrect

Thus, the correct answer is **Option 2: CH₃-CHCl-CH₂I**.

---