Which of the following is correct for
`CH_(3)- CH= CH_(2) overset(HBr)underset("Peroxide")(to) ?

Options

A. Electrophilic soubstitution
B. Anti- Markovnikov's addition
C. Nucleophilic substitution
D. Markovnikov's addition

Answer

To solve the question regarding the reaction of CH₃-CH=CH₂ with HBr in the presence of peroxide, we can follow these steps:

### Step 1: Identify the Reactants
The reactant is CH₃-CH=CH₂, which is propene. It has a double bond between the second and third carbon atoms.

**Hint:** Look for the structure of the alkene to understand where the double bond is located.

### Step 2: Understand the Reaction Conditions
The reaction is taking place with HBr in the presence of peroxide. The presence of peroxide is crucial because it influences the mechanism of the reaction.

**Hint:** Remember that peroxide affects the regioselectivity of the addition reaction.

### Step 3: Determine the Type of Addition
In the presence of peroxide, the reaction follows the anti-Markovnikov rule. This means that the hydrogen atom from HBr will add to the carbon with the greater number of hydrogen atoms (the terminal carbon), while the bromine will add to the other carbon.

**Hint:** Recall the anti-Markovnikov rule, which states that the less substituted carbon receives the electrophile when peroxides are present.

### Step 4: Predict the Product
When HBr adds to CH₃-CH=CH₂ under these conditions:
- The hydrogen (H) will attach to the terminal carbon (C1), which has more hydrogen atoms.
- The bromine (Br) will attach to the second carbon (C2).

The product will be CH₃-CH(Br)-CH₃, which is 1-bromopropane.

**Hint:** Visualize the addition of H and Br to the alkene to determine the final product.

### Step 5: Conclusion
The correct answer to the question is that the reaction results in an anti-Markovnikov addition of HBr to the alkene.

**Final Answer:** The correct option is "anti-Markovnikov addition."