`C_(6)H_(5)CH_(3) overset(Br_(2)//FeBr_(3))(to)` the reaction is called

Options

A. Nucleophilic substitution
B. Free radical addition
C. Electrophilic substitution
D. Free radical substitution

Answer

To determine the type of reaction that occurs when toluene (C₆H₅CH₃) reacts with bromine (Br₂) in the presence of iron(III) bromide (FeBr₃), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are toluene (C₆H₅CH₃) and bromine (Br₂) in the presence of a catalyst, iron(III) bromide (FeBr₃).

2. **Understand the Structure of Toluene**: Toluene consists of a benzene ring (C₆H₅) with a methyl group (CH₃) attached. The methyl group is an electron-donating group, which activates the benzene ring towards electrophilic substitution reactions.

3. **Role of FeBr₃**: Iron(III) bromide (FeBr₃) acts as a Lewis acid and helps generate a more reactive electrophile from bromine. It does this by forming a complex with bromine, leading to the generation of the bromonium ion (Br⁺).

4. **Electrophilic Attack**: The activated benzene ring (due to the presence of the methyl group) will attack the electrophile (Br⁺). This results in the substitution of a hydrogen atom on the benzene ring with a bromine atom.

5. **Product Formation**: The product formed from this reaction is para-bromotoluene (C₆H₄BrCH₃), as the methyl group directs the incoming bromine to the para position relative to itself due to its electron-donating effect.

6. **Type of Reaction**: Since the reaction involves the substitution of a hydrogen atom in the benzene ring by a bromine atom, it is classified as an electrophilic substitution reaction.

### Final Answer:
The reaction of C₆H₅CH₃ with Br₂ in the presence of FeBr₃ is called **electrophilic substitution**.

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