The product obtained by reduction of benzyl bromide with `LIAIH_(4)` is

Options

A.
B.
C.
D.

Answer

To solve the question regarding the product obtained by the reduction of benzyl bromide with lithium aluminum hydride (LiAlH4), we can follow these steps:

### Step-by-Step Solution:

1. **Identify Benzyl Bromide**:
- Benzyl bromide is a compound that consists of a benzene ring (C6H5) attached to a CH2 group, which is further attached to a bromine atom (Br).
- The structure can be represented as:
\[ \text{C}_6\text{H}_5\text{CH}_2\text{Br} \]

2. **Understanding the Reducing Agent**:
- Lithium aluminum hydride (LiAlH4) is a strong reducing agent that provides hydride ions (H-).
- These hydride ions can replace halogen atoms in organic compounds.

3. **Reaction Mechanism**:
- When benzyl bromide is treated with LiAlH4, the Br atom is replaced by a hydride ion (H-).
- The reaction can be summarized as follows:
\[ \text{C}_6\text{H}_5\text{CH}_2\text{Br} + \text{LiAlH}_4 \rightarrow \text{C}_6\text{H}_5\text{CH}_3 + \text{LiBr} + \text{AlBr}_3 \]
- Here, the Br- ion is released, and the H- from LiAlH4 attaches to the carbon atom, converting it to a methyl group (CH3).

4. **Final Product**:
- The final product of this reduction is toluene (C6H5CH3), which is the hydrocarbon formed after the removal of the bromine atom.

### Conclusion:
The product obtained by the reduction of benzyl bromide with LiAlH4 is **toluene**.